Given a binary tree, return the inorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3}
,
1
\
2
/
3
return [1,3,2]
.
Note: Recursive solution is trivial, could you do it iteratively?
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> inorderTraversal(TreeNode *root) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
vector<int> vt;
if (!root){
return vt;
}
std::stack<TreeNode *> stk;
TreeNode * p = root;
while(!stk.empty() || p){
while(p){
stk.push(p);
p = p->left;
}
if (!stk.empty()){
TreeNode * q = stk.top();
stk.pop();
vt.push_back(q->val);
if (q->right){
p = q->right;
}else{
p = NULL;
}
}
}
return vt;
}
};
原文链接: https://www.cnblogs.com/kwill/archive/2013/06/06/3122809.html
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