1 class Solution {
2 public:
3 vector<int> searchRange(int A[], int n, int target) {
4 // Start typing your C/C++ solution below
5 // DO NOT write int main() function
6 vector<int> v(2,-1);
7
8 int l = 0, m , r = n-1;
9
10 while( l<=r )
11 {
12 m = l + (r-l)/2;
13 if(A[m]<target)
14 l = m+1;
15 else
16 r = m - 1;
17 }
18 if( l<n && A[l] == target ) v[0] = l;
19 else return v;
20
21 l = l+1; r = n - 1;
22 while( l<=r )
23 {
24 m = l + (r-l)/2;
25 if(A[m]<=target)
26 l = m+1;
27 else
28 r = m - 1;
29 }
30 if( r>=0 && A[r] == target ) v[1] = r;
31
32 return v;
33
34 }
35 };
原文链接: https://www.cnblogs.com/jumpinGGrass/p/3169975.html
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