count and say

string countAndSay(int n) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        string s = "1";
        while( n>1 )
        {
            string t="";

            int i = 0;
            while( i < s.length() )
            {
                int count = 1;
                while(i+1<s.length() && s[i+1]==s[i] )
                {
                    count++;
                    i++;
                }    
                char m =  count + '0' ;
                t = t + m;
                t = t + s[i];
                i ++;

            }
            s = t;
            n--;

        }
        return s;
    }

原文链接: https://www.cnblogs.com/jumpinGGrass/p/3170116.html

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