#include<iostream> using namespace std; int main() { int *p = new int[10]; for(int i = 0; i < 10; i++) { cout << p[i] << endl; } delete []p; }
这个我们都知道,在堆上申请的数组是不会进行初始化,结果为随机值。
这种呢?
#include<iostream> using namespace std; int main() { int *p = new int[10](); for(int i = 0; i < 10; i++) { cout << p[i] << endl; } delete []p; }
It is valid in C++, the relevant part of the standard is 5.3.4, with the first paragraph containing the grammar
Paragraph 5.3.4/15 states that
A new-expression that creates an object of type T initializes that object as follows:
...
- If the new-initializer is of the form (), the item is value-initialized (8.5)
原文链接: https://www.cnblogs.com/lgh1992314/archive/2013/03/09/5835174.html
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