xcode下编译报错:ISO C++ forbids declaration of 'iterator' with no type
出错点:
template<class T> class MyVector: public std::vector<T> { public: typedef std::vector<T> vecType; typedef vecType::iterator vecIterator; //报错 MyVector(){}; MyVector(const vecType& _vec); //....... //....... };
根据别人的回答,http://stackoverflow.com/questions/1732895/error-iso-c-forbids-declaration-of-iterator-with-no-type。找到原因:
“The reason being being that iterator
is dependent on what T is, so the compiler can't be sure it's a typename unless you tell it.”
加 typename,修改后编译通过:
template<class T> class MyVector: public std::vector<T> { public: typedef std::vector<T> vecType; typedef typename vecType::iterator vecIterator; //typename MyVector(){}; MyVector(const vecType& _vec); //....... //....... };
mark! 还有一点“C++编译器不能支持对模板的分离式编译”,why? google.....
原文链接: https://www.cnblogs.com/fjut/archive/2013/03/08/2950634.html
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