CUDA与C++

1.使用thrust:

http://stackoverflow.com/questions/13185221/cuda-host-object-to-device

http://blog.csdn.net/shenlan282/article/details/8237576

http://blog.csdn.net/shenlan282/article/details/8237586

2.使用条件编译

http://stackoverflow.com/questions/6978643/cuda-and-classes

Define the class in a header that you #include, just like in C++.

Any method that must be called from device code should be defined with both __device__ and__host__ declspecs,
including the constructor and destructor if you plan to use new/delete on
the device (note new/delete require
CUDA 4.0 and a compute capability 2.0 or higher GPU).

You probably want to define a macro like

#ifdef __CUDACC__
#define CUDA_CALLABLE_MEMBER __host__ __device__
#else
#define CUDA_CALLABLE_MEMBER
#endif 

Then use this macro on your member functions

class Foo {
public:
    CUDA_CALLABLE_MEMBER Foo() {}
    CUDA_CALLABLE_MEMBER ~Foo() {}
    CUDA_CALLABLE_MEMBER void aMethod() {}
};

The reason for this is that only the CUDA compiler knows __device__ and __host__ --
your host C++ compiler will raise an error.

原文链接: https://www.cnblogs.com/Vulkan/archive/2012/11/30/7530193.html

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