The book <<C++ templates>> said:
however, in VS2008 and gcc 4.3, the compilers can deduce the type of parameter. The followed code has no compile error.
look here(http://ideone.com/yTpaJ ) for gcc result.
#include <vector>
#include <algorithm>
using namespace std;
template <typename T, int VAL>
T addValue (T const& x) {
return x + VAL;
}
int main(int argc, char* argv[])
{
vector<int> source;
vector<int> dest;
int (*funP)(int const&);
funP = addValue<int,5>;
std::transform (source.begin(), source.end(), // start and end of source
dest.begin(), // start of destination
addValue<int,5>); // operation
std::transform (source.begin(), source.end(), // start and end of source
dest.begin(), // start of destination
funP);
return 0;
}
原文链接: https://www.cnblogs.com/aoaoblogs/archive/2011/07/06/2099052.html
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